X^2=X-(1-i)

Solution for X^2=X-(1-i) equation:

X^2=X-(1-X)

We move all terms to the left:

X^2-(X-(1-X))=0

We add all the numbers together, and all the variables

X^2-(X-(-1X+1))=0


We calculate terms in parentheses: -(X-(-1X+1)), so:

X-(-1X+1)

We get rid of parentheses

X+1X-1

We add all the numbers together, and all the variables

2X-1

Back to the equation:

-(2X-1)


We get rid of parentheses

X^2-2X+1=0

a = 1; b = -2; c = +1;
Δ = b2-4ac
Δ = -22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{2}{2}=1$